Distance between cities › Canada › Alberta › Arrowwood, AB › Distance from Arrowwood to Swalwell

Distance from Arrowwood, AB to Swalwell, AB

Distance

116 km

Time

1 hour 48 mins

Gas Cost

$8 - $18

There are 92.19 km (57.29 miles) from Arrowwood to Swalwell in north direction and 115.87 km (72 miles) by car, following the 21 route.

Arrowwood and Swalwell are 1 hour 48 mins far apart, if you drive non-stop .

This is the fastest route from Arrowwood, AB to Swalwell, AB. The halfway point is Strathmore, AB.

Arrowwood, AB and Swalwell, AB are in the same time zone (MDT). Current time in both locations is 12:58 am.

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Gas Consumption and Emissions

A car with a fuel efficiency of 8.9 l/100 km will need 10.30 liters of gas to cover the route between Arrowwood, AB and Swalwell, AB.

The estimated cost of gas to go from Arrowwood to Swalwell is $13.67.

During the route, an average car will release 246.45 kilograms of CO₂ to the atmosphere. The carbon footprint would be 2.13 kilograms of CO₂ per kilometer.

Average Canada gas price used for calculation is $1.33 per liter of regular gas. Price last updated on April 28, 2017.
Read more about our CO₂ calculation.

Best Hotels In or Near Swalwell, AB

Do you have where to stay when you arrive to Swalwell, AB? Check out our hotel recommendations:

Halfway Point Between Arrowwood, AB and Swalwell, AB

If you want to meet halfway between Arrowwood, AB and Swalwell, AB or just make a stop in the middle of your trip, the exact coordinates of the halfway point of this route are 51.062172 and -113.260956, or 51º 3' 43.8192" N, 113º 15' 39.4416" W. This location is 35.97 miles away from Arrowwood, AB and Swalwell, AB and it would take approximately 54 minutes to reach the halfway point from both locations.

Closest City or Town to Halfway Point

The closest town to the halfway point is Strathmore, AB, situated 38 miles from Arrowwood, AB and 46 miles from Swalwell, AB. It would take 47 minutes to go from Arrowwood to Strathmore and 1 hour 14 mins to go from Swalwell to Strathmore.