Distance between cities › USA › Wisconsin › Cedarburg, WI › Distance from Cedarburg to Antioch

Distance from Cedarburg, WI to Antioch, IL

Distance

69 mi

Time

1 hour 16 mins

Gas Cost

$7 - $13

There are 56.89 miles from Cedarburg to Antioch in south direction and 69 miles (111.04 kilometers) by car, following the I-94 E route.

Cedarburg and Antioch are 1 hour 16 mins far apart, if you drive non-stop .

This is the fastest route from Cedarburg, WI to Antioch, IL. The halfway point is Caledonia, WI.

Cedarburg, WI and Antioch, IL are in the same time zone (CDT). Current time in both locations is 3:47 am.

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Gas Consumption and Emissions

A car with a fuel efficiency of MPG will need 2.78 gallons of gas to cover the route between Cedarburg, WI and Antioch, IL.

The estimated cost of gas to go from Cedarburg to Antioch is $9.35.

During the route, an average car will release 54.45 pounds of CO₂ to the atmosphere. The carbon footprint would be 0.79 pounds of CO₂ per mile.

Average USA gas price used for calculation is $3.37 per gallon of regular gas. Price last updated on April 16, 2024.
Read more about our CO₂ calculation.

Best Hotels In or Near Antioch, IL

Do you have where to stay when you arrive to Antioch, IL? Check out our hotel recommendations:

Halfway Point Between Cedarburg, WI and Antioch, IL

If you want to meet halfway between Cedarburg, WI and Antioch, IL or just make a stop in the middle of your trip, the exact coordinates of the halfway point of this route are 42.842365 and -87.949715, or 42º 50' 32.514" N, 87º 56' 58.974" W. This location is 34.60 miles away from Cedarburg, WI and Antioch, IL and it would take approximately 38 minutes to reach the halfway point from both locations.

Closest City or Town to Halfway Point

The closest town to the halfway point is Caledonia, WI, situated 40 miles from Cedarburg, WI and 33 miles from Antioch, IL. It would take 48 minutes to go from Cedarburg to Caledonia and 36 minutes to go from Antioch to Caledonia.