Distance between cities › USA › Ohio › Cleveland › Distance from Cleveland to Pittsburgh

Distance from Cleveland, OH to Pittsburgh, PA

Distance

133 mi

Time

2 hours 9 mins

Gas Cost

$13 - $25

There are 114.90 miles from Cleveland to Pittsburgh in southeast direction and 133 miles (214.04 kilometers) by car, following the I-80 E route.

Cleveland and Pittsburgh are 2 hours 9 mins far apart, if you drive non-stop .

This is the fastest route from Cleveland, OH to Pittsburgh, PA. The halfway point is Austintown, OH.

Cleveland, OH and Pittsburgh, PA are in the same time zone (EDT). Current time in both locations is 1:54 pm.

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Gas Consumption and Emissions

A car with a fuel efficiency of MPG will need 5.33 gallons of gas to cover the route between Cleveland, OH and Pittsburgh, PA.

The estimated cost of gas to go from Cleveland to Pittsburgh is $17.89.

During the route, an average car will release 104.36 pounds of CO₂ to the atmosphere. The carbon footprint would be 0.79 pounds of CO₂ per mile.

Average USA gas price used for calculation is $3.36 per gallon of regular gas. Price last updated on April 26, 2024.
Read more about our CO₂ calculation.

Best Hotels In or Near Pittsburgh, PA

Do you have where to stay when you arrive to Pittsburgh, PA? Check out our hotel recommendations:

Halfway Point Between Cleveland, OH and Pittsburgh, PA

If you want to meet halfway between Cleveland, OH and Pittsburgh, PA or just make a stop in the middle of your trip, the exact coordinates of the halfway point of this route are 41.079964 and -80.806885, or 41º 4' 47.8704" N, 80º 48' 24.786" W. This location is 66.32 miles away from Cleveland, OH and Pittsburgh, PA and it would take approximately 1 hour 4 mins to reach the halfway point from both locations.

Closest City or Town to Halfway Point

The closest town to the halfway point is Austintown, OH, situated 68 miles from Cleveland, OH and 72 miles from Pittsburgh, PA. It would take 1 hour 9 mins to go from Cleveland to Austintown and 1 hour 16 mins to go from Pittsburgh to Austintown.