Distance between cities › USA › Indiana › Jasonville, IN › Distance from Jasonville to Linton Book Hotels

Distance from Jasonville, IN to Linton, IN

Distance

10 mi

Time

19 minutes

Gas Cost

$1 - $2

There are 9.04 miles from Jasonville to Linton in southeast direction and 10 miles (16.09 kilometers) by car, following the SR 59 route.

Jasonville and Linton are 19 minutes far apart, if you drive non-stop .

This is the fastest route from Jasonville, IN to Linton, IN.

Jasonville, IN and Linton, IN are in the same time zone (EDT). Current time in both locations is 11:04 pm.

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Lowest Price Rental Cars in Jasonville, IN

Planning on renting a car to go from Jasonville, IN to Linton, IN? Here there are some offers to rent a car in Jasonville, IN

Small

From $14

Intermediate

From $18

Full-size

From $24

SUVs

From $28

Vans

From $40

Compare rental car prices in Jasonville »

Gas Consumption and Emissions

A car with a fuel efficiency of MPG will need 0.42 gallons of gas to cover the route between Jasonville, IN and Linton, IN.

The estimated cost of gas to go from Jasonville to Linton is $1.55.

During the route, an average car will release 8.24 pounds of CO₂ to the atmosphere. The carbon footprint would be 0.79 pounds of CO₂ per mile.

Average USA gas price used for calculation is $3.68 per gallon of regular gas. Price last updated on March 18, 2026.
Read more about our CO₂ calculation.

Recommended hotels in Linton, IN

Looking for a place to stay in Linton, IN? Check out these hotel deals:

Halfway Point Between Jasonville, IN and Linton, IN

If you want to meet halfway between Jasonville, IN and Linton, IN or just make a stop in the middle of your trip, the exact coordinates of the halfway point of this route are 39.098190 and -87.185074, or 39º 5' 53.484" N, 87º 11' 6.2664" W. This location is 5.24 miles away from Jasonville, IN and Linton, IN and it would take approximately 9 minutes to reach the halfway point from both locations.