Distance between cities › USA › Michigan › Lake Angelus, MI › Distance from Lake Angelus to Atlanta

Distance from Lake Angelus, MI to Atlanta, MI

Distance

190 mi

Time

3 hours 16 mins

Gas Cost

$20 - $38

There are 164.58 miles from Lake Angelus to Atlanta in northwest direction and 190 miles (305.78 kilometers) by car, following the I-75 N route.

Lake Angelus and Atlanta are 3 hours 16 mins far apart, if you drive non-stop .

This is the fastest route from Lake Angelus, MI to Atlanta, MI. The halfway point is Linwood, MI.

Lake Angelus, MI and Atlanta, MI are in the same time zone (EDT). Current time in both locations is 9:53 pm.

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Gas Consumption and Emissions

A car with a fuel efficiency of MPG will need 7.61 gallons of gas to cover the route between Lake Angelus, MI and Atlanta, MI.

The estimated cost of gas to go from Lake Angelus to Atlanta is $27.80.

During the route, an average car will release 149.14 pounds of CO₂ to the atmosphere. The carbon footprint would be 0.79 pounds of CO₂ per mile.

Average USA gas price used for calculation is $3.65 per gallon of regular gas. Price last updated on April 18, 2024.
Read more about our CO₂ calculation.

Best Hotels In or Near Atlanta, MI

Do you have where to stay when you arrive to Atlanta, MI? Check out our hotel recommendations:

Halfway Point Between Lake Angelus, MI and Atlanta, MI

If you want to meet halfway between Lake Angelus, MI and Atlanta, MI or just make a stop in the middle of your trip, the exact coordinates of the halfway point of this route are 43.778866 and -84.013885, or 43º 46' 43.9176" N, 84º 0' 49.986" W. This location is 94.77 miles away from Lake Angelus, MI and Atlanta, MI and it would take approximately 1 hour 38 mins to reach the halfway point from both locations.

Closest City or Town to Halfway Point

The closest town to the halfway point is Linwood, MI, situated 93 miles from Lake Angelus, MI and 102 miles from Atlanta, MI. It would take 1 hour 27 mins to go from Lake Angelus to Linwood and 2 hours 1 min to go from Atlanta to Linwood.