Distance between cities › USA › Connecticut › Melrose, CT › Distance from Melrose to Annada

Distance from Melrose, CT to Annada, MO

Distance

2,039 mi

Time

1 day 5 hours

Gas Cost

$196 - $381

There are 1,707.41 miles from Melrose to Annada in east direction and 2,039 miles (3,281.45 kilometers) by car, following the I-80 route.

Melrose and Annada are 1 day 5 hours far apart, if you drive non-stop .

This is the fastest route from Melrose, CT to Annada, MO. The halfway point is Sinclair, WY.

Please note the time difference between Melrose, CT and Annada, MO is 2 hours. The current time in Melrose is 10:45 am and the current time in Annada is 12:45 pm.

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Gas Consumption and Emissions

A car with a fuel efficiency of MPG will need 81.87 gallons of gas to cover the route between Melrose, CT and Annada, MO.

The estimated cost of gas to go from Melrose to Annada is $275.57.

During the route, an average car will release 1,603.99 pounds of CO₂ to the atmosphere. The carbon footprint would be 0.79 pounds of CO₂ per mile.

Average USA gas price used for calculation is $3.37 per gallon of regular gas. Price last updated on April 16, 2024.
Read more about our CO₂ calculation.

Best Hotels In or Near Annada, MO

Do you have where to stay when you arrive to Annada, MO? Check out our hotel recommendations:

Halfway Point Between Melrose, CT and Annada, MO

If you want to meet halfway between Melrose, CT and Annada, MO or just make a stop in the middle of your trip, the exact coordinates of the halfway point of this route are 41.775204 and -107.067368, or 41º 46' 30.7344" N, 107º 4' 2.5248" W. This location is 1,019.28 miles away from Melrose, CT and Annada, MO and it would take approximately 14 hours 42 mins to reach the halfway point from both locations.

Closest City or Town to Halfway Point

The closest town to the halfway point is Sinclair, WY, situated 1,045 miles from Melrose, CT and 1,000 miles from Annada, MO. It would take 14 hours 34 mins to go from Melrose to Sinclair and 14 hours 59 mins to go from Annada to Sinclair.