Distance between cities › USA › Texas › Howe, TX › Distance from Howe to Allen Book Hotels

Distance from Howe, TX to Allen, OK

Distance

104 mi

Time

2 hours 2 mins

Gas Cost

$10 - $19

There are 95.36 miles from Howe to Allen in north direction and 104 miles (167.37 kilometers) by car, following the OK 48 route.

Howe and Allen are 2 hours 2 mins far apart, if you drive non-stop .

This is the fastest route from Howe, TX to Allen, OK. The halfway point is Caney, OK.

Howe, TX and Allen, OK are in the same time zone (CDT). Current time in both locations is 3:51 am.

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Lowest Price Rental Cars in Howe, TX

Planning on renting a car to go from Howe, TX to Allen, OK? Here there are some offers to rent a car in Howe, TX

Small

From $14

Intermediate

From $18

Full-size

From $24

SUVs

From $28

Vans

From $40

Compare rental car prices in Howe »

Gas Consumption and Emissions

A car with a fuel efficiency of MPG will need 4.18 gallons of gas to cover the route between Howe, TX and Allen, OK.

The estimated cost of gas to go from Howe to Allen is $13.76.

During the route, an average car will release 81.92 pounds of CO₂ to the atmosphere. The carbon footprint would be 0.79 pounds of CO₂ per mile.

Average USA gas price used for calculation is $3.29 per gallon of regular gas. Price last updated on March 13, 2026.
Read more about our CO₂ calculation.

Halfway Point Between Howe, TX and Allen, OK

If you want to meet halfway between Howe, TX and Allen, OK or just make a stop in the middle of your trip, the exact coordinates of the halfway point of this route are 34.238354 and -96.221657, or 34º 14' 18.0744" N, 96º 13' 17.9652" W. This location is 52.05 miles away from Howe, TX and Allen, OK and it would take approximately 1 hour 1 min to reach the halfway point from both locations.

Closest City or Town to Halfway Point

The closest town to the halfway point is Caney, OK, situated 59 miles from Howe, TX and 60 miles from Allen, OK. It would take 52 minutes to go from Howe to Caney and 1 hour 10 mins to go from Allen to Caney.