Distance between cities › USA › South Dakota › Lane, SD › Distance from Lane to Best Book Hotels

Distance from Lane, SD to Best, TX

Distance

1,138 mi

Time

20 hours 39 mins

Gas Cost

$106 - $206

There are 904.37 miles from Lane to Best in south direction and 1,138 miles (1,831.43 kilometers) by car, following the US-81 route.

Lane and Best are 20 hours 39 mins far apart, if you drive non-stop .

This is the fastest route from Lane, SD to Best, TX.

Lane, SD and Best, TX are in the same time zone (CDT). Current time in both locations is 3:37 am.

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Lowest Price Rental Cars in Lane, SD

Planning on renting a car to go from Lane, SD to Best, TX? Here there are some offers to rent a car in Lane, SD

Small

From $14

Intermediate

From $18

Full-size

From $24

SUVs

From $28

Vans

From $40

Compare rental car prices in Lane »

Gas Consumption and Emissions

A car with a fuel efficiency of MPG will need 45.70 gallons of gas to cover the route between Lane, SD and Best, TX.

The estimated cost of gas to go from Lane to Best is $149.07.

During the route, an average car will release 895.31 pounds of CO₂ to the atmosphere. The carbon footprint would be 0.79 pounds of CO₂ per mile.

Average USA gas price used for calculation is $3.26 per gallon of regular gas. Price last updated on March 12, 2026.
Read more about our CO₂ calculation.

Halfway Point Between Lane, SD and Best, TX

If you want to meet halfway between Lane, SD and Best, TX or just make a stop in the middle of your trip, the exact coordinates of the halfway point of this route are 36.984572 and -97.345665, or 36º 59' 4.4592" N, 97º 20' 44.394" W. This location is 568.94 miles away from Lane, SD and Best, TX and it would take approximately 10 hours 19 mins to reach the halfway point from both locations.

Closest City or Town to Halfway Point

The closest town to the halfway point is Hunnewell, KS, situated 575 miles from Lane, SD and 568 miles from Best, TX. It would take 10 hours 35 mins to go from Lane to Hunnewell and 10 hours 17 mins to go from Best to Hunnewell.