Distance between cities › USA › Illinois › Rio, IL › Distance from Rio to Ingram Book Hotels

Distance from Rio, IL to Ingram, TX

Distance

1,088 mi

Time

20 hours 55 mins

Gas Cost

$101 - $197

There are 908.62 miles from Rio to Ingram in southwest direction and 1,088 miles (1,750.97 kilometers) by car, following the I-44 route.

Rio and Ingram are 20 hours 55 mins far apart, if you drive non-stop .

This is the fastest route from Rio, IL to Ingram, TX.

Rio, IL and Ingram, TX are in the same time zone (CDT). Current time in both locations is 2:28 pm.

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Lowest Price Rental Cars in Rio, IL

Planning on renting a car to go from Rio, IL to Ingram, TX? Here there are some offers to rent a car in Rio, IL

Small

From $14

Intermediate

From $18

Full-size

From $24

SUVs

From $28

Vans

From $40

Compare rental car prices in Rio »

Gas Consumption and Emissions

A car with a fuel efficiency of MPG will need 43.69 gallons of gas to cover the route between Rio, IL and Ingram, TX.

The estimated cost of gas to go from Rio to Ingram is $142.51.

During the route, an average car will release 855.95 pounds of CO₂ to the atmosphere. The carbon footprint would be 0.79 pounds of CO₂ per mile.

Average USA gas price used for calculation is $3.26 per gallon of regular gas. Price last updated on March 12, 2026.
Read more about our CO₂ calculation.

Halfway Point Between Rio, IL and Ingram, TX

If you want to meet halfway between Rio, IL and Ingram, TX or just make a stop in the middle of your trip, the exact coordinates of the halfway point of this route are 36.301944 and -95.320696, or 36º 18' 6.9984" N, 95º 19' 14.5056" W. This location is 543.92 miles away from Rio, IL and Ingram, TX and it would take approximately 10 hours 27 mins to reach the halfway point from both locations.

Closest City or Town to Halfway Point

The closest town to the halfway point is Pryor, OK, situated 525 miles from Rio, IL and 563 miles from Ingram, TX. It would take 10 hours 8 mins to go from Rio to Pryor and 10 hours 46 mins to go from Ingram to Pryor.